[Celtibero]

con roll for Dana plz or no roll if your char is answering truthfully

[JackVII]

If no one has a better way of getting the maglock open, I can try to Shatter it or the door.

[Bewilderbeast]

Lies of omission are still lies, so let's call it a Con roll. 5 hits: http://orokos.com/roll/190583

[martinchaen]

Nicely played, Bewilderbeast, that was an excellent con (and con roll!)

[Celtibero]

@Vandarl

u have 3 marks on the commlink i need you to do 1 thing:

spoof maglock to open roll plz not running silent

[Vandarl]

One genuine spoof command!
http://orokos.com/roll/191099 Results   11d6: 28 [11d6=6, 2, 2, 1, 2, 2, 2, 5, 4, 1, 1]

if that does not succeed I will give it another shot.
http://orokos.com/roll/191101 Results   11d6: 24 [11d6=4, 1, 4, 1, 1, 3, 3, 1, 3, 2, 1]

Burning an edge to reroll
http://orokos.com/roll/191103 Results   11d6: 41 [11d6=4, 4, 6, 4, 3, 1, 1, 5, 6, 6, 1]

Stinkin awful maglock, Grrr!

[martinchaen]

Hey Vandarl, just FYI you can type 6d6t5 to get results compiled for you. The t5 part at the end specifies to the roller that it should count 5s and 6s.

[Celtibero]

hit count  example 6d6t5

exploding dice example - 6d6o6n5 ( "o6" rerolls all "6's"; "n5 counts and up as hits)

[martinchaen]

Some quick public Matrix Searches using my Browse program (threshold 1 with additional hits reducing search time by (base time divided by net hits)). I find this very odd, because the more hits you get the less time is reduced. 1 minute divided by 1 net hit is 1 minute, meaning the search is reduced by 1 minute as the rule is written. Get 5 net hits and the reduction is (60/5=12)  12 seconds. That can't be right. I'm taking this to mean that the "base time divided by net hits" means that that is how long it takes for the search to complete in total. So, 1 net hit on a 1 minute interval = 1 minute. 5 net hits on a 1 minute interval = the search takes 12 seconds.

[EDIT]
Updated search times as per the below.

Matrix Search w/Browse [6]: "Komun'Go Seoulpa overview": 12d6t5 4
30 second base / 3 net hits = 10 seconds total
30 second base time / 3 net hits + 1 = 7.5 seconds total

Matrix Search w/Browse [6]: "Komun'Go Seoulpa activity in Seattle": 12d6t5 2
30 second base / 3 net hits = 30 seconds total
30 second base time / 1 net hit + 1 = 15 seconds total

Matrix Search w/Browse [6]: "Relationship between Komun'Go Seoulpa and Choson Seoulpa in Seattle": 12d6t5 4
30 second base / 3 net hits = 10 seconds total
30 second base time / 3 net hits + 1 = 7.5 seconds total

So, 50 30 seconds total search time. After that, Moto will spend some time researching both of the Seoulpa rings looking for known and suspected activity in Seattle on private boards and similar, for a Threshold 3 test with a base time of 15 minutes (due to Browse).
Matrix Search w/Browse [6]: "Komun'Go Seoulpa and Choson Seoulpa known and suspected activities in Seattle": 12d6t5 3
15 minutes base / 0 net hits + 1 = 15 minutes total

[Celtibero]

Some quick public Matrix Searches using my Browse program (threshold 1 with additional hits reducing search time by (base time divided by net hits)). I find this very odd, because the more hits you get the less time is reduced. 1 minute divided by 1 net hit is 1 minute, meaning the search is reduced by 1 minute as the rule is written. Get 5 net hits and the reduction is (60/5=12)  12 seconds. That can't be right. I'm taking this to mean that the "base time divided by net hits" means that that is how long it takes for the search to complete in total. So, 1 net hit on a 1 minute interval = 1 minute. 5 net hits on a 1 minute interval = the search takes 12 seconds.

Hmm the threshold is how difficult it is to get the info, any net hits (imo) is the added skill that makes the search go faster, but on 1 net hit you gain nothing. thus imho it should be:

base search time / (net hits +1)
 1m/(1+1) =30s
1m/(2+1)=20s
1m/(5+1)=10s

the difference isn't much, but as the rule is framed it gives you zero reward for being above the threshold by 1 hit.

[JackVII]

For clarification, am I correct in my understanding that Cormack and the Baron have climbed three flights of stairs on the exterior of the building and are at the door that leads into the hotel?

[Celtibero]

yes, they are on the 1st floor back entrance.

[JackVII]

yes, they are on the 1st floor back entrance.

So we're not on the third floor? I'm apparently having trouble visualizing this. Is the stairway internal to the building or on the outside (like a fire escape). Also... is this place open-roofed? It sounds like one f those buildings with a large courtyard in the middle that the rooms surround.

[Celtibero]

they are on teh 1st floor, its sort of a fire escape, it leads just to the 1st floor, the interior stairwell and elevator lead to all the 3 floors.

[JackVII]

OK, so we do need to go inside the building to gain access to the third floor.  So, there is a security door in the northwest corner, an interior stairwell in the northeast corner, an elevator in the southwest corner, and another door that leads to the first floor which I would guess is in the southeast corner?

Is the interior of the building open to the sky?